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Originally Posted by catalina_marina
Quote:
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Originally Posted by Michiel
You mean no one actually knew/calculated that last one? Cat?
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Of course I did. You should have put 7 in there though. At first I hadn't noticed you only had two of those things. :roll: |
So it's 7 tries with 3 balls, I assume? How does that work, anyway? My first guess was binary search until you have two balls left, but that proved not to be optimal.